1. If the current age is x, then n times the age is nx.

2. If the current age is x, then age n years later/hence = x + n.

3. If the current age is x, then age n years ago = x – n.

4. The ages in a ratio a : b will be ax and bx.

5. If the current age is x, then

1

of the age is

x

.

n

n

Problems on Ages -General Questions

1.

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?

A.

2 times

B.

2

1

times

2

C.

2

3

times

4

D.

3 times

Answer: Option A

Explanation:

Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.

(4x + 8) =

5

(x + 8)

2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio =

(4x + 16)

=

48

= 2.

(x + 16)

24

2.

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

A.

4 years

B.

8 years

C.

10 years

D.

None of these

Answer: Option A

Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?

Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is

Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?