Calender-Simplest aptitude Tricks

METHOD TO FIND THE DAY OF  WEEK FOR  THE GIVEN DATE

Example:25th February,1998

STEP 1: Take the last two digits of the year(Here.. 98)

Divide the last two digits of the year by 4 and then take its quotient value(Here… 98/4=24 is the quotient and   2 is the remainder.Consider 24(quotient is always a number without decimal i.e.,2/4 quotient=0 .Its not 0.5 ))

STEP 2: Add the day of the month.( In our example, 24 + 25 = 49)

STEP 3:Add the month’s key value, from the following table.

MONTH CODE:

Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec
1 4 4 0 2 5 0 3 6 1 4 6

The month for our example is February , with a key value of 4.(4+49=53)

STEP 4: If your date is in January or February of a leap year, subtract 1. We’re using February but 1998 is not a leap year, so we don’t have to worry about this step.

Way to find whether a year is a leap year or not:

  • If year is not an exact century i.e.,hundredth years(examples:100,200,500,600,1800,6000…….):Then                                       divide the year by 4.If we get a remainder of zero then year is a leap year
  • Example:1996(1996/4 remainder=0 .So 1996 is a leap year),1204,1608,1840….
  • If year is an exact century : Then  divide the year by 400.If we get a remainder of zero then year is a leap year
  • Example:2000,2400,1600,1200… are leap years and 100,200,300,500,1500…. are not leap years

STEP 5: Add the century code from the following table. (These codes are for the Gregorian calendar. The rule’s slightly simpler for Julian dates.)

CENTURY CODE:

1600s 1700s 1800s 1900s 2000s 2100s 2200s 2300s …..
6 4 2 0 6 4 2 0 …..

Similarly,Future years century code can be found by repeating series of 6,4,2,0… and  even its previous centuries code can be found by the same method accordingly…(i.e.,1200-6,1300-4,1400-2,1500-0)

In our example,53+0=53

STEP 6: Add the last two digits of the year(Here,53+98=151)

STEP 7:Divide by 7 and take the remainder.

WEEK CODE:

Sunday Monday Tuesday Wednesday Thursday Friday Saturday
1 2 3 4 5 6 0

In our example,151/7 the remainder=4 and quotient=21

As,the remainder=4, by week’s code of above table it is wednesday

  • So,finally the formula to find the day of a week is:
  • {week code of[quotient of(quotient of (last two digits of a year/4)+(day of month)+(month  code)=(century code)+(last two digits of year))/7]}

 

 

 

What was the day of the week on 28th May, 2006?

What was the day of the week on 17th June, 1998?

What will be the day of the week 15th August, 2010?

what was the day of the week on 6th March, 2004?

What was the day of the week on 8th Feb, 2005?

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