# Calender-Simplest aptitude Tricks

##### METHOD TO FIND THE DAY OF  WEEK FOR  THE GIVEN DATE

Example:25th February,1998

STEP 1: Take the last two digits of the year(Here.. 98)

Divide the last two digits of the year by 4 and then take its quotient value(Here… 98/4=24 is the quotient and   2 is the remainder.Consider 24(quotient is always a number without decimal i.e.,2/4 quotient=0 .Its not 0.5 ))

STEP 2: Add the day of the month.( In our example, 24 + 25 = 49)

STEP 3:Add the month’s key value, from the following table.

MONTH CODE:

 Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec 1 4 4 0 2 5 0 3 6 1 4 6

The month for our example is February , with a key value of 4.(4+49=53)

STEP 4: If your date is in January or February of a leap year, subtract 1. We’re using February but 1998 is not a leap year, so we don’t have to worry about this step.

Way to find whether a year is a leap year or not:

• If year is not an exact century i.e.,hundredth years(examples:100,200,500,600,1800,6000…….):Then                                       divide the year by 4.If we get a remainder of zero then year is a leap year
• Example:1996(1996/4 remainder=0 .So 1996 is a leap year),1204,1608,1840….
• If year is an exact century : Then  divide the year by 400.If we get a remainder of zero then year is a leap year
• Example:2000,2400,1600,1200… are leap years and 100,200,300,500,1500…. are not leap years

STEP 5: Add the century code from the following table. (These codes are for the Gregorian calendar. The rule’s slightly simpler for Julian dates.)

CENTURY CODE:

 1600s 1700s 1800s 1900s 2000s 2100s 2200s 2300s ….. 6 4 2 0 6 4 2 0 …..

Similarly,Future years century code can be found by repeating series of 6,4,2,0… and  even its previous centuries code can be found by the same method accordingly…(i.e.,1200-6,1300-4,1400-2,1500-0)

In our example,53+0=53

STEP 6: Add the last two digits of the year(Here,53+98=151)

STEP 7:Divide by 7 and take the remainder.

WEEK CODE:

 Sunday Monday Tuesday Wednesday Thursday Friday Saturday 1 2 3 4 5 6 0

In our example,151/7 the remainder=4 and quotient=21

As,the remainder=4, by week’s code of above table it is wednesday

• So,finally the formula to find the day of a week is:
• {week code of[quotient of(quotient of (last two digits of a year/4)+(day of month)+(month  code)=(century code)+(last two digits of year))/7]}