Important notes on Principal Related to Practical Chemistry for CBSE & IIT-JEE

Principal Related to Practical Chemistry is one of the most important topics from CBSE & IIT-JEE perspective. So make sure that you go through these notes to score the most!

Qualitative Analysis of Organic Compounds:

This is used to detect nitrogen, halogen and sulphur present in organic compound.

a) Sodium Extract:Aqueous solution containing soluble sodium salt of the elements i.e NaCl, Na2S and NaCNS formed by fusion of compound with sodium metal.

b) Formation of Sodium Extract: It is a two-step process.

Step 1: Organic compounds are fused with dry sodium in a fusion-tube.

Step 2: Fused mass after extraction with water is boiled and filtered.

c) Use of Sodium Extract: Sodium extract (S.E.) is used to detect elements (other than C and H) and the tests are given in the table.

Element Sodium Extract (S.E.) Confirmed Test
Nitrogen Na + C + N +Δ→ NaCl S.E.+ FeSO4 +NaOH, boil and cool

+

FeCl3 + conc. HCl → Blue/ green colour

 

Reactions Involved:

Sulphur 2Na + S → Na2S (i) S.E. + sodium nitroprusside → Violet Colour

(ii) S.E + CH3CO2H + (CH3CO2)2Pb → black ppt.

 

Reactions Involved:

Halogen Na +X + Δ→ NaX (X = Cl, Br, I) S.E. + HNO3+AgNO3

(i) White ppt soluble in aq NH3 confirms Cl.

(ii) Pale yellow ppt partially soluble in aq. NH3 confirms Br.

(iii) Yellow ppt insoluble in aq. NH3 confirms I.

 

Reactions Involved:

Nitrogen and sulphur together Na+ C + N + S+ Δ→ NaCNS with excess of Na the thiocyanate formed decomposes into cyanide and sulphide. NaCNS + 2Na → NaCN +Na2S As in test for nitrogen; instead of green or blue colour, blood red colouration confirms presence of N and S both.

 

Reactions Involved:

 

ALSO READ:

Important Questions of Modern Physics for IIT-JEE mains and advance

Qualitative Analysis of Inorganic Salts:

1. Physical Examination of Salts/Mixture

Observation Inference
1. Substance is coloured
i) Blue Copper salt
ii) Dark green Chromium salt
iii) Green Salts of Fe(II), Ni, Cu or Cr
iv) Light yellow or brown Salts of Fe(III)
v) Dark brown PbO2,Bi2S3
vi) Light pink Salts of Mn
vii) Pink Salts of Co
viii) Red HgO, HgI2,Pb3O4
ix) Orange red Sb2S3
2. Substance is deliquescent CaCl2,ZnCl2,MgCl2, MnCl2, nitrites, nitrates
3. Substance is heavy Salts of Pb, Hg and Ba
4. Substance is light Carbonates of Bi, Mg, Al, Zn, Ca, Sr

 

2. Effect of Heating:

Observation Inference
1. Substance melts Salts of alkali metals and salts having water of crystallisation.
2. Substance decripitates (crackling noise) NaCl, KI, Pb(NO3)2 and Ba(NO3)2
3. Substance swells (due to loss of water of crystallisation) Alums, borates and phosphates
4. The substance sublimes and the colour of sublimate is
i) White HgCl2, Hg2Cl2,NH4X, AlCl3, As2O3, Sb2O3
ii) Yellow As2S3 and HgI2 (turns red when rubbed with glass rod).
iii) Blue black and violet vapours Iodides
5. A residue (generally oxide) is left and its colour is
i) Yellow (hot) and white (cold) ZnO
ii) Reddish brown (hot); yellow (cold) PbO
iii) Black (hot); Red (cold) HgO, Pb3O4
iv) Black (hot); Red brown (cold) F Fe2O3
6. Gas is evolved
(A) Colourless and odourless
i) O2 – rekindles a glowing splinter Alkali nitrates (2KNO3 → 2KNO2 + O2
ii) CO2 – turns lime water milky Carbonates and oxalates (CaCO3 → CaO + CO2)
iii) N2 Ammonium nitrite (NH4NO2 → N2 + 2H2O)
(B) Colourless gas with odour
i) NH3 – Turns red litmus blue and mercurous nitrate paper black Ammonium salts (NH4)2SO4 → NH4HSO4 + NH3
ii) SO2 – Smell of burning sulphur, turns acidified K2Cr2O7 paper green Sulphites and thiosulphates CaSO3 →CaO + SO2
iii) HCl – Pungent smell, white fumes with ammonia Hydrated chlorides CaCl2.6H2O → Ca(OH)2 + 4H2O + 2HCl
iv) H2S – smell of rotten eggs, turns lead acetate paper black Sulphides Na2S + 2H2O → 2NaOH + H2S
(C) Coloured gas
i) NO2 – Brown, turns starch iodide paper blue Nitrites and nitrates of heavy metals 2Cu(NO3)2 → 2CuO + 4NO2 + O2
ii) Br2 – Reddish brown Bromides 2CdBr2 + O2 → 2CdO + 2Br2
(A) Turns starch paper yellow
(B) turns starch iodide paper blue
iii) I2 – Violet, turns starch paper blue Iodides 2CdI2 + O2 → 2CdO + 2I2
iv) Cl2 – Greenish yellow Chlorides
(A) bleaches moist litmus paper CuCl2 + H2O → CuO + 2HCl CuO + 2HCl → Cu + H2O + Cl2
(B) bleaches indigo solution
(C) turns starch iodide paper blue

 

ALSO READ:

Short Notes of Modern Physics for IIT-JEE mains and advance

3. Flame test:

Metals Colour
Li crimson red
Na golden yellow
K Violet
Ca Brick red
Sr Crimson
Ba apple green

 

Test for Anions:

 

1. Carbonate (CO32- )

i) Dilute HCl : gives effervescence, due to the evolution of carbon dioxide

CO32- + 2H+ → CO2 + H2O

The gas gives turbidity with lime water and baryta water.

CO2 + Ca2+ + 2OH- → CaCO3¯ + H2O

CO2 + Ba2+ + 2OH-→ BaCO3¯ + H2O

On prolonged passage of carbon dioxide in lime water, the turbidity slowly disappears due to the formation of soluble hydrogen carbonate.

CaCO3¯ → + CO2 + H2O → Ca(HCO3)2

ii) Barium chloride or Calcium chloride solution: White ppt of barium or calcium carbonate is obtained, which is soluble in mineral acid.

CO32- + Ba2+ → BaCO3¯

CO32- + Ca2+ → CaCO3¯

iii) Silver nitrate solution: White ppt of silver carbonate is obtained.

CO32- + 2Ag+ → Ag2CO3¯

The ppt so obtained is soluble in nitric acid and in ammonia. The ppt becomes yellow or brown on addition of excess reagent and same may also happen if the mix is boiled, due to the formation of silver oxide.

Ag2CO3¯ → Ag2O¯ + CO2

ALSO READ:

Short notes of Electro Chemistry for IIT-JEE Main and Advance

 

2. Sulphites (SO32- )

i) Dilute HCl or Dilute H2SO4 : decomposes with the evolution of sulphur dioxide

SO32- + 2H+ → SO2 + H2O

The gas has a suffocating odour of burning sulphur.

ii) Acidified potassium dichromate solution: Turns filter paper moistened with acidified potassium dichromate solution, green due to the formation of Cr3+ions.

iii) Lime water : On passing the gas through lime water, a milky ppt is formed. Precipitate dissolves on prolonged passage of the gas, due to the formation of hydrogen sulphite ions.

iv) Barium chloride or Strontium chloride solution: Gives white ppt. of barium or strontium sulphite.

 

3. Sulphide (S-2 )

i) Dil. HCl or Dil. H2SO4: A colourless gas smelling of rotten eggs (H2S) is evolved.

S2- + 2H+ → H2S

ii) The gas turns lead acetate paper black

iii) Gives yellow ppt. with CdCO3 Na2S + CdCO3 → CdS¯ + Na2CO3

iv) Silver nitrate solution: black ppt. of silver sulphide insoluble in cold but soluble in hot dil nitric acid.

S2- + 2Ag+ → Ag2S¯

v) Sodium nitroprusside solution : Turns sodium nitroprusside solution purple

Na2S + Na2[Fe(CN)5NO] → Na4[Fe(CN5NOS]

ALSO READ:

Important notes on Bio molecules for CBSE & IIT-JEE

 

4. Nitrites (NO2 )

i) Dil HCl and Dil. H2SO4 : Adding to solid nitrite in cold yields pale blue liquid (due to the presence of free nitrous acid HNO2 or its anhydride N2O3) & the evolution of brown fumes of nitrogen dioxide, the latter being largely produced by combination of nitric oxide with the oxygen of the air

i) Silver nitrate solution : White crystalline ppt. is obtained

NO2 + Ag + → AgNO2¯

iii) Turns acidified KI – starch paper blue

2KI + 2NO2 → 2KNO2 + I2

Starch + I2 → Blue colour

iv) Brown ring test: When the nitrite solution is added carefully to a conc. solution of Iron(II) sulphate acidified with dil acetic acid or with dilute sulphuric acid, a brown ring is formed, due to the formation of [FeNO]SO4 at the junction of the two liquids.

 

5. Acetate (CH3COO)

i) Dilute Sulphuric Acid : Smell of vinegar is observed.

CH3COO + H+ → CH3COOH

The following test is performed with the aqueous salt solution.

ii) Iron (III) Chloride Solution: Gives deep – red colouration

CH3COONa + FeCl3 → (CH3COO)3Fe + 3NaCl Brown colour

ALSO READ:

Important notes on Chemistry in everyday life for CBSE & IIT-JEE

 

6. Thiosulphates

i) Dil Hydrochloric acid: Gives sulphur & sulphur di oxide

ii) Silver nitrate solution: Gives white ppt. of silver thiosulphate.

S2O32- + 2Ag+<s/sup> → Ag2S2O3¯

The ppt. is unstable, turning dark on standing, when silver sulphide is formed.

Ag2S2O3¯ + H2O → Ag2S + H2SO4

iii) Lead acetate or Lead nitrate solution: Gives white ppt.

S2O32- + Pb2+ → PbS2O3¯

On boiling it turns black due to the formation of PbS.

PbS2O3¯ + H2O →PbS¯ + 2H+ + SO42

 

7. Chloride (Cl)

i) Conc. H2SO4 : decomposes with the evolution of HCl.

Cl + H2SO4 → HCl + HSO

Gas so produced

(ii) Turns blue litmus paper red

(iii) Gives white fumes of NH4Cl when a glass rod moistened with ammonia solution is brought near the mouth of test tube.

(iv) Silver nitrate solution: White, curdy ppt. of AgCl insoluble in water & in dil .nitric acid, but soluble in dilute ammonia solution.

(v) Chromyl chloride test: When a salt containing chloride ion is heated with K2Cr2O7 and conc. H2SO4 orange red fumes of chromyl chloride (CrO2Cl2) are formed.

K2Cr2O7 + 4NaCl + 6H2SO4 → 2KHSO4 + 4NaHSO4 + 2CrO2Cl2 + 3H2O

orange – red fumes

Chlorides of mercury, owing to their slight ionization, do not respond to this test and only partial conversion to CrO2Cl2 occurs with the chlorides of lead, silver, antimony and tin.

When chromyl chloride vapours are passed into sodium hydroxide a yellow solution of sodium chromate is formed which when treated with lead acetate gives yellow ppt. of lead chromate.

CrO2Cl2 + 2NaOH → Na2CrO4 + 2HCl

Yellow solution

Na2CrO4 + (CH3COO)2 Pb → 2CH3COONa + PbCrO4 ¯ (yellow ppt.)

ALSO READ:-

Important notes on Organic Compound containing Nitrogen for CBSE & IIT-JEE

 

8. Bromide (Br)

i) Conc. H2SO4 : Gives reddish brown vapours of bromine accompanying the hydrogen bromide.

ii) Manganese dioxide and conc. sulphuric acid : When a mix of solid bromide, MnO2 and conc. H2SO4 is heated reddish brown vapours of bromine are evolved.

2KBr + MnO2 + 2H2SO4 → Br2 + K2SO4> + MnSO4 + 2H2O

The following tests are performed with the aqueous salt solution.

iii) Silver nitrate solution: Pale yellow ppt. of silver bromide is obtained. This ppt. is sparingly soluble in dil but readily soluble in conc. ammonia solution and insoluble in dil. HNO3.

iv) Lead acetate solution: White crystalline ppt. of lead bromide which is soluble in boiling water.

 

9. Iodide (I)

i) Conc. H2SO4 : Gives violet vapours of iodine

ii) Silver nitrate solution: Yellow ppt. of silver iodide AgI, very slightly soluble in conc. ammonia solution and insoluble in dil nitric acid.

ALSO READ:

Important notes on Aldehyde, ketone or carboxylic Acids for CBSE & IIT-JEE

 

10. Nitrate (NO3 )

i) Conc H2SO4 : Gives reddish – brown vapours of nitrogen dioxide

4NO3 + 2H2SO4 → 4NO2 + 2SO42- + 2H2O + O2

ii) Brown ring test: When freshly saturated solution of iron

(II) sulphate is added to nitrate solution and conc. H2SO4 is poured slowly down the side of the test – tube, a brown ring is obtained. 2NO3 – + 4H2SO4 + 6Fe2+ → 6Fe3+ +2NO + 4SO4–2 + 4H2O Fe2+ + NO → [Fe(NO)]2+ On shaking and warming the mix, the brown colour disappears, nitric oxide is evolved and a yellow solution of Iron(III) ions remains.

 

11. Sulphate (SO42- )

i) Barium chloride solution: White ppt. of barium sulphate BaSO4 insoluble in warm dil. hydrochloric acid and in dilute nitric acid, but moderately soluble in boiling, conc. hydrochloric acid.

ii) Mercury (II) nitrate solution: Gives yellow ppt. of basic mercury (II) sulphate

ALSO READ :-

Short Notes of Complex Numbers for IIT-JEE mains and advance

 

12. Chromate CrO42 -and Dichromate (Cr2O)

i) Barium chloride solution: Pale – yellow ppt. of barium chromate soluble in dilute mineral acids but insoluble in water and acetic acid.

CrO + Ba2+ → BaCrO4¯

Dichromate ion also gives the same ppt. but due to the formation of strong acid precipitation is partial.

Cr2O+ 2Ba2+ +  H2O  2BaCrO4¯  + 2H+

If sodium hydroxide or sodium acetate is added, precipitation becomes quantitative.

ii) Silver Nitrate Solution: Brownish – red ppt. of silver chromate Ag2CrO4 which is soluble in dil. nitric acid & in ammonia solution, but insoluble in acetic acid.

A reddish brown ppt. of silver dichromate Ag2Cr2O7 is formed with a conc. solution of a dichromate.

 

13. Permanganate MnO

i) Hydrogen peroxide : It decolourises acidified potassium permanganate solution

2MnO4 +  5H2O2 +  6H+ ¾¾® 5O2  +  2Mn2+ + 8H2O

ii) Iron (II) sulphate, in the presence of sulphuric acid, reduces permanganate to manganese (II). The solution becomes yellow because of the formation of iron (III) ions

MnO4 + 5Fe2+ + 8H+ → 5Fe3+ + Mn2+ + 4H2O

 

JEE Mains Crash Course offered by Eckovation

To prepare for the JEE main Exam, one needs a platform where all their problems should be solved with clear concepts. At Eckovation, you will find the following:
1. Chapter wise Notes
2. Chapter wise Practice Papers
3. Mock Tests
4. All India Test Series
5. Chapter wise Video Lectures
6. Counselling
7. Peer Discussion

To Join the crash course and study with IIT Delhi Graduates: Click Here

 

Don't miss out!
Subscribe To Our Newsletter

Learn new things. Get an article everyday.

Invalid email address
Give it a try. You can unsubscribe at any time.

Leave a Reply

Your email address will not be published. Required fields are marked *